16-6.Distributed load such as double-point support beam

16-6. Distributed load such as double-point support beam Symbol description and unit
Maximum deflection�F(mm)
ƒÂmax(x=0)=1/24*‚—*L1*(3*L13+6*L12*L2-L23)/(E*I)
ƒÂmax(x=0)=
ƒÂmax(x=L/2)=1/384*‚—*L22*(5*L22-24*L12)/(E*I)
ƒÂmax(x=L/2)=

Maximum stress�F (Kg/mm2)
ƒÐmax=M(x=L1)/Z=1/2*‚—*L12/Z
ƒÐmax=
ƒÐmax=M(x=L/2)/Z=1/2*‚—*L2*(L1/L-1/4)/Z
ƒÐmax=
E�FYoung's modulus(Kg/mm2)
Steel:21000
Stainless steel:19000
Aluminum:7000
cast iron:10000

I�F Moment of inertia of area(mm4)
Z�F Moment of inertia (mm3)
‚—�F Load B (Kg/mm)
L�F Beam length (mm)
L1�FBeam length to load position (mm)
L2�FBeam length to load position (mm)
Reference: "Machine Design Handbook for Engineers" (Revised version by Saburo Kano) Applied Structural Mechanics Beam Calculation Table, page 142, refer to beams and columns.